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A pendulum clock was moved from a location where g = 9.8135 m/s 2 to another location where g = 9.7943 m/s 2 . During the move, the length of the clock’s pendulum did not change; nevertheless, the clock lost accuracy. Assuming the clock was perfectly accurate at its previous location, how many seconds a day does it lose at the new location?

Respuesta :

gilcarusolautaro

Answer:

The pendulum clock does it loses 83.0304 seconds a day at the new location.

Explanation:

T1= 1 s

T2= ?

g1= 9.8135 m/s

g2= 9.7943 m/s

L=?

L= (T1/2π)²  * g1=

L= 0.24857m

T2= 2π * √(L/g2)

T2= 1.000961 s

ΔT= T2 - T1

ΔT = 0.000961 s

seconds lost a day = 24 * 3600 * ΔT

seconds lost a day= 24 * 3600 * 0.000961 s

seconds lost a day= 83.0304 s

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