Answer:
No, A″C″B″ is located at A″(1, 1), C″(4, 3), and B″(1, 5)
Step-by-step explanation:
The triangle has vertices A(1,1), B(5,1), C(3,4).
First transformation is reflection over y-axis with the rule
(x,y)→(-x,y)
so,
Second transformation is rotation by 270° counterclockwise with the rule
(x,y)→(y,-x)
so
No, A″C″B″ is located at A″(1, 1), C″(4, 3), and B″(1, 5)