Answer:
204.1 Hz
Explanation:
The fundamental frequency of a vibrating string is given by:
[tex]f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}[/tex]
where
L is the length of the string
T is the tension in the string
[tex]\mu[/tex] is the linear mass density of the string
For the wire in this problem, we have
L = 2.00 m
T = 8.00 kN = 8000 N
[tex]\mu = 12.0 g/m = 0.012 kg/m[/tex]
Therefore, substituting into the equation, we find the frequency of the string:
[tex]f=\frac{1}{2(2.00 m)}\sqrt{\frac{8000 N}{0.012 kg/m}}=204.1 Hz[/tex]
