#11 A student measures a samples mass to 45.5 g. the true mass is determined later to be 42.3 g. What is the students percent error

Answer:
7.565 %.
Explanation:
Error % = [True value - Measured value) /True value] ×100
where, True value = 42.3 g.
Measured value = 45.5 g.
Error % = [║(True value - Measured value)║ /True value] ×100
Error % = [║(42.3 g) - (45.5 g)║ /(42.3 g)] × 100 = 7.565 %.