ANSWER
(-2,-1)
(3,14)
EXPLANATION
The given system is
[tex]y = {x}^{2} + 2x - 1[/tex]
[tex] y - 3x = 5[/tex]
or
[tex]y = 3x + 5[/tex]
Equate both of them:
[tex]{x}^{2} + 2x - 1 = 3x + 5[/tex]
This implies that,
[tex]{x}^{2} - x - 6 = 0[/tex]
[tex](x - 3)(x + 2) = 0[/tex]
x=-2 or x=3
When x=-2, y=y=3(-2)+5=-1
(-2,-1) is a solution.
When x=3 , y=3(3)+5=14
(3,14) is also a solution.
