Answer: 16%
Step-by-step explanation:
Given: Mean : [tex]\mu = 200\text{ pounds}[/tex]
Standard deviation : [tex]\sigma=50\text{ pounds}[/tex]
The formula for z score is given by :-
[tex]z=\dfrac{x-\mu}{\sigma}[/tex]
Now, for x=250
[tex]z=\dfrac{250-200}{50}=1[/tex]
The P-value [tex]= P(z>1)=1-P(z<1)[/tex]
[tex]=1-0.8413=0.1587\approx16\%[/tex]
Hence, the percent of the adult pandas weigh over 250 pounds is about 16%.
