Josh is having issues with his over-the-range microwave, and must decide to either have it repaired or replaced. After doing some research, he's determined that if he has to spend $200 or more on repairs, the better decision would be to replace the microwave. The appliance repair company will repair his microwave for a service call fee of $89, a parts fee of $41, and a charge of $17.50 for every 15 minutes of labor. If x represents the number of 15-minute intervals of labor, which inequality represents the number of allowable 15-minute intervals before replacing the microwave becomes the better decision? Assume that Josh won't be charged for a 15-minute interval until the full 15 minutes of labor is used.

add all of the numbers together and the x with the 17.50. Add a less than inequality sign, then 200, which represents how much it would be for repairs

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chisnau chisnau · Answer 2 · 2019-09-06T14:59:58+02:00

Answer:

[tex]130+17.50x \leq 200[/tex]

Step-by-step explanation:

The appliance repair company will repair his microwave for a service call fee of $89, a parts fee of $41, and a charge of $17.50 for every 15 minutes of labor.

If Josh spends $200 or more on repairs, he will replace the microwave.

Let x represents the number of 15-minute intervals of labor.

So, as per the scenario, the inequality becomes:

[tex]89+41+17.50x \leq 200[/tex]

=> [tex]130+17.50x \leq 200[/tex]

Solving for x

[tex]17.50x \leq 200-130[/tex]

[tex]17.50x \leq 70[/tex]

[tex]x \leq 4[/tex]

Hence, up to 4, 15 minutes interval that is one hour. the repair cost will be up to $200.

But after this it will cost more. Hence, Josh can opt for replacing after 4, 15 minutes intervals.