Answer:
a) 4 - [tex]vt - d = \frac{1}{2} at^{2}[/tex]
b) 1 - [tex]2(vt - d) = at^{2}[/tex]
c) 6 - [tex]\frac{2(vt - d)}{t^{2}} = a[/tex]
Step-by-step explanation:
It simply asks the steps to go from the original displacement formula to isolate a (the acceleration). It's just a matter of moving items around.
We start with:
[tex]d = vt - \frac{1}{2} at^{2}[/tex]
We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):
[tex]vt - d = \frac{1}{2} at^{2}[/tex]
Then we multiply each side by 2 to get rid of the 1/2, answer #1:
[tex]2(vt - d) = at^{2}[/tex]
Finally, we divide each side by t^2 to isolate a (answer #6):
[tex]\frac{2(vt - d)}{t^{2}} = a[/tex]
