assuming simple interest.
[tex]\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$1500\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\dotfill &6 \end{cases} \\\\\\ A=1500[1+(0.05)(6)]\implies A=1500(1.3)\implies A=1950[/tex]
