Answer:
[tex]\cos^{-1}(\frac{6.3}{9.8})[/tex]
[tex]\sin^{-1}(\frac{7.5}{9.8})[/tex]
Step-by-step explanation:
Recall the mnemonics SOH-CAH-TOA
The sine ratio is the length of the opposite side expressed over the hypotenuse.
[tex]\sin m\angle ABC=\frac{7.5}{9.8}[/tex]
Take the sine inverse of both sides to get;
[tex]m\angle ABC=\sin^{-1}(\frac{7.5}{9.8})[/tex]
The cosine ratio is the length of the adjacent side expressed over the hypotenuse.
[tex]\cos m\angle ABC=\frac{6.3}{9.8}[/tex]
Take the cosine inverse of both sides to get;
[tex]m\angle ABC=\cos^{-1}(\frac{6.3}{9.8})[/tex]
