Answer:
[tex]4.8\cdot 10^{-21} N[/tex]
Explanation:
The force exerted by a magnetic field on a charged particle is given by
[tex]F=qvB[/tex]
where
q is the charge of the particle
v is the speed
B is the magnetic field strength
In this problem we have:
[tex]B = 0.20 T[/tex] is the strength of the magnetic field
[tex]v = 15 cm/s = 0.15 m/s[/tex] is the velocity
[tex]q=e = 1.6\cdot 10^{-19}C[/tex] is the magnitude of the charge of a single chlorine ion
Substituting into the equation,
[tex]F=(1.6\cdot 10^{-19} C)(0.15 m/s)(0.20 T)=4.8\cdot 10^{-21} N[/tex]
