given: f(x) = x + 2 and g(x) = 3x + 5
f (x)/g (x) =

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carlosego carlosego · Answer 1 · 2019-05-16T19:30:50+02:00

For this case we have two functions of the form y = f (x). We must find the quotient of the following functions:

[tex]f (x) = x + 2\\g (x) = 3x + 5[/tex]

So, we have by definition:

[tex]\frac {f (x)} {g (x)} = \frac {x + 2} {3x + 5}[/tex]

Answer:

[tex]\frac {f (x)} {g (x)} = \frac {x + 2} {3x + 5}[/tex]

with 3x + 5 different from zero, so that the function is defined

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kudzordzifrancis kudzordzifrancis · Answer 2 · 2019-05-16T19:33:57+02:00

Answer:

[tex]\frac{f(x)}{g(x)}=\frac{x+2}{3x+5}[/tex]

where [tex]x\ne -\frac{5}{3}[/tex]

Step-by-step explanation:

The given functions are:

f(x) = x + 2 and g(x) = 3x + 5

[tex]\frac{f(x)}{g(x)}=\frac{x+2}{3x+5}[/tex]

Since this is a rational function, the function will not be defined where denominator equals zero.

We need to restrict the function or define the domain.

This is a rational function defined for [tex]x\ne -\frac{5}{3}[/tex]

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