The equation of the line that passes through points (0,-7) and (2,-1) is shown below.What value is missing from the equation?

For this case we have that by definition, the slope-intersection equation of a line is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cutoff point with the y axis
[tex]m = \frac {y2-y1} {x2-x1} = \frac {-1 - (- 7)} {2-0} = \frac {-1 + 7} {2} = \frac {6} { 2} = 3[/tex]
Thus, the equation is:
[tex]y = 3x + b[/tex]
Substituting a point we find b:[tex]-7 = 0 + b\\b = -7[/tex]
Finally the equation is:
[tex]y = 3x-7[/tex]
ANswer:
The missing value is 3
Answer:
The value of missing is 3
Step-by-step explanation:
* To form an equation of a line from two points on the line, you
must find the slope of the line at first
- The form of the equation is y = mx + c, where m is the slope of the
line and c is the y-intercept
- The rule of the slope of a line passes through point (x1 , y1) and (x2 , y2)
is m = (y2 - y1)/(x2 - x1)
* Lets solve the problem
∵ (0 , -7) and (2 , -1) are tow points on the line
- Let (0 , -7) is the point (x1 , y1) and (2 , -1) is the point (x2 , y2)
∴ m = (-1 - -7)/(2 - 0) = (-1 + 7)/2 = 6/2 = 3
- Lets write the equation
∴ y = 3x + c
- c is the y-intercept means the line intersect the y-axis at point (0 , c)
∵ Point (0 , -7) on the line
∴ The line intersect the y-axis at point (0 , -7)
∴ The y-intercept is -7
∴ The equation of the line is y = 3x - 7
* The value of missing is 3