Answer:
a. E=1440KJ
b. E=360KJ
c. E=1.8 J
Explanation:
I have the power (Watts) is expressed as Energy (Joules) / Time (seconds), also I have to[tex]1hour * \frac{60min}{1hour}*\frac{60s}{1min}\\1h=3600s[/tex]
so, for the lightbulb
[tex]100W= \frac{Energy}{3600s*4}\\Energy=100W*14400s\\ E=1440000J =1440KJ[/tex]
Analogously, for the microwave
[tex]1200W= \frac{Energy}{60s*5}\\Energy=1200W*300s\\ E=360000J =360KJ[/tex]
Now, I have to express the efficiency as Heat energy / power * 100 so[tex]1.8= \frac{Heat Energy}{100W}*100\\Heat Energy=1.8J[/tex]
Done