By DeMoivre's theorem,
[tex](\sqrt2(\cos10^\circ+i\sin10^\circ))^6=(\sqrt2)^6(\cos60^\circ+i\sin60^\circ)[/tex]
[tex]=8(\cos60^\circ+i\sin60^\circ)[/tex]
The answer is 8(cos60° +isin 60°)
Demoivre's theorem:, De Moivre's formula (also known as de Moivre's theorem and de Moivre's identity) states that for any real number x and integer n it holds that (cosx + i sinx)^n= cosnx + i sinnx.
where i is the imaginary unit (i2 = −1).
By DeMoivre's theorem:
[sqrt(2)(cos(10)+isin(10)]^6
(√2 (cos 1o° + isin 10°))^6 = (√2)^6(cos 60° + isin 60°)
=8(cos60° +isin 60°)
Learn more about demoivre'stheorem: https://brainly.com/question/27650810
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