Isolate “y” in one of the equations, then substitute it in the other equation. After you find x, put it in the isolated equation and you’ll find y value.
The value of x = 1 and y = 0.
Consider the given system of equation
4x - 2y = 4 ........(1)
6x - 4y = 6 ........(2)
Solve the system algebraically,
By using the elimination method,
Multiply equation (1) by 2, and we get,
(1) ⇒ 8x - 4y = 8 ............(3)
Subtract equation (2) from (3), we get,
8x - 4y - (6x - 4y) = 8 - 6
Simplifying the above equation, we get
8x - 4y - 6x + 4y = 2
8x - 6x = 2
⇒ x = 1
Substitute x = 1 in (1) and solve for y, we get,
⇒ 4x - 2y = 4
⇒ 4 (1) - 2y = 4
⇒ 2y = 4 - 4
⇒ 2y = 0
⇒ y = 0
Therefore, the value of x = 1 and y = 0.
To learn more about algebraic expression
https://brainly.com/question/12111796
#SPJ2
