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solve the following quadratic equation for x by completing the square and solve x^2-8x=-65​

Respuesta :

Answer:

x= 4-7i  x= 4+ 7i

Step-by-step explanation:

step 1 : make equation = 0

[tex]x^{2}[/tex] - 8x + 65 = 0

step 2 : solve for x [ using the quadratic equation]

ie :     x = -b ± [tex]\sqrt{b^{2}-4ac}[/tex] / 2a

so it will look like this

x= -(-8) ± [tex]\sqrt{(-8)^{2} - 4(1)(65)}[/tex] /2(1)

when you simplify you wont be able to root the -196 so you will have to separate the roots

x = 8 ±( [tex]\sqrt{-1}[/tex] )( [tex]\sqrt{196}[/tex]) / 2

now there is a rule for negative roots whereby  [tex]\sqrt{-1}[/tex] is equivalent to i so now you will change [tex]\sqrt{-1}[/tex] into i

Simplify [tex]\sqrt{196}[/tex]

which will give you 14

now place all the new values into the formula

8 ± 14i /2

you can then further simplify to  

4 ± 7i

step 3 : separate

this will give you the final answer of

x= 4 + 7i   x= 4- 7i

Answer:

x = 4+7i and x=4-7i

Step-by-step explanation:

I just did the test

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