Answer:
x= 4-7i x= 4+ 7i
Step-by-step explanation:
step 1 : make equation = 0
[tex]x^{2}[/tex] - 8x + 65 = 0
step 2 : solve for x [ using the quadratic equation]
ie : x = -b ± [tex]\sqrt{b^{2}-4ac}[/tex] / 2a
so it will look like this
x= -(-8) ± [tex]\sqrt{(-8)^{2} - 4(1)(65)}[/tex] /2(1)
when you simplify you wont be able to root the -196 so you will have to separate the roots
x = 8 ±( [tex]\sqrt{-1}[/tex] )( [tex]\sqrt{196}[/tex]) / 2
now there is a rule for negative roots whereby [tex]\sqrt{-1}[/tex] is equivalent to i so now you will change [tex]\sqrt{-1}[/tex] into i
Simplify [tex]\sqrt{196}[/tex]
which will give you 14
now place all the new values into the formula
8 ± 14i /2
you can then further simplify to
4 ± 7i
step 3 : separate
this will give you the final answer of
x= 4 + 7i x= 4- 7i
Answer:
x = 4+7i and x=4-7i
Step-by-step explanation:
I just did the test