For this case we have that the pigs have 4 legs while the hens have 2.
We propose a system of equations:
x: Variable representing the number of pigs
y: Variable representing the number of chickens
[tex]x + y = 37\\4x + 2y = 124[/tex]
We multiply by -4 the first equation:
[tex]-4x-4y = -148[/tex]
We add the equations:
[tex]-4x-4y = -148\\4x + 2y = 124\\-4y + 2y = -148 + 124\\-2y = -24\\y = \frac {24} {2}\\y = 12[/tex]
So, there are 12 chickens.
[tex]x + 12 = 37\\x = 37-12\\x = 25[/tex]
There are 25 pigs.
ANswer:
25 pigs
12 chickens
Option C
