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Write a program that calculates the average of n integers. the program should prompt the user to enter the value for n and then afterward must enter all n numbers. if the user enters a nonpositive value for n, then an exception should be thrown (and caught) with the message "n must be positive." if there is any exception as the user is entering the n numbers, an error message should be displayed, and the user prompted to enter the number again.

Respuesta :

khaif

#include<studio.h>

int main( )

{

int n;

int a,b,c,d,x,y;

int avarage;

printf("enter value of n:\n");

scanf("%d",&n);

printf("enter value of a:\n,b:\n,c:\n,d:\n,x:\n,y:\n);

scan f("%d\%d\n%d\n%d\n%d\n%d\n",&a,b,c,d,x,y);

sum=(a+b+c+d+x+y);

avarage=(sum/n);

print f("%d",avarage);

if

{

n=positive interger

}

else

{

printf ("n must be positive");

}

return 0;

}

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