Please help !
Graph the line.
-3x + y = -9

Answer:
See attachment
Step-by-step explanation:
The given function is
[tex]-3x+y=-9[/tex]
We make y the subject to get;
[tex]y=3x-9[/tex]
This function has a y-intercept of (0,-9) and a slope 3.
Also when y=0,
[tex]-3x+0=-9[/tex]
[tex]-3x=-9[/tex]
[tex]x=3[/tex]
The x-intercept is (3,0)
We plot the intercepts and draw a straight line through them to obtain the graph in the attachment.
The graph is attached.
To graph a line, we first need to know:
- If the slope is increasing or decreasing
- Calculate the interception point with the axis
The slope of a line indicates if the function is increasing or decreasing.
We are given the function:
[tex]-3x+y=-9\\y=3x-9[/tex]
The slope is the coefficient of the variable (x), for this case, it's a positive value and it means that the function is increasing.
Calculating the interception points:
Let's make the function equal to 0 in order to find y-axis intercept:
[tex]y=3x-9\\0=3x-9\\3x=9\\x=\frac{9}{3}=3[/tex]
Then, substituting "x" into the function to find the y-axis interception point, we have:
[tex]y=3*3-9\\y=9-9=0[/tex]
The first interception point is (3,0)
To find the second interception point, let's make "x" equal to 0:
[tex]y=3*0-9\\y=0-9=-9[/tex]
Then, substituting "y" into the function to find the x-axis interception point, we have:
[tex]y=3x-9\\-9=3x-9\\-9+9=3x\\0=3x\\x=0[/tex]
The second interception point is (0,-9)
Therefore,
We have a line which has a positive slope (increasing function) and intercepts the axis at (3,0) and (0,-9)
See the attached image for the graphic.
Have a nice day!