The graph shows the height (h), in feet, of a basketball t seconds after it is shot. Projectile motion formula: h(t) = -16t2 + vt + h0 v = initial vertical velocity of the ball in feet per second h0 = initial height of the ball in feet Complete the quadratic equation that models the situation. h(t) = –16t2 + t + 6 Image description

Respuesta :

Answer:

h(t) = –16t^2 + 46*t + 6

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The projectile formula is

h(t) = -16*t^2 + v*t + h0

Where,

v = initial vertical velocity of the ball in feet per second

h0 = initial height of the ball in feet

We need to fill the equation

h(t) = –16t^2 + v*t + 6

Where

v is the missing speed

If we go through many values of v until we find the same graph as the one showed in the first picture, we can find that

v = 46 ft/s

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Answer:

h(t) = –16t2 + 24t + 6

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