If cot(theta)= 4/3, find csc(theta) (Picture provided)

Answer:
D
Step-by-step explanation:
If [tex]\cot \theta=\dfrac{4}{3},[/tex] then we can consider right triangle with adjacent leg 4 un. and opposite leg 3 un.. By the Pythagorean theorem,
[tex]\text{hypotenuse}^2=\text{adjacent leg}^2+\text{opposite leg}^2,\\ \\\text{hypotenuse}^2=4^2+3^2,\\ \\\text{hypotenuse}^2=16+9,\\ \\\text{hypotenuse}^2=25,\\ \\\text{hypotenuse}=5\ un.[/tex]
So,
[tex]\csc \theta=\dfrac{\text{hypotenuse}}{\text{opposite leg}}=\dfrac{5}{3}.[/tex]
Answer:
The correct answer is option d
Step-by-step explanation:
Trigonometric ratio
Cot θ = Adjacent side/Opposite side
It is given that,
Cot θ = 4/3
Adjacent side = 4
Opposite side = 3
Csc θ = Hypotenuse/Opposite side
To find the Hypotenuse
Hypotenuse² = Opposite side² + Adjacent side ² = 3²+ 4²
Hypotenuse = √(3²+ 4²) = 5
To find Csc θ
Csc θ = Hypotenuse/Opposite side = 5/3
The correct answer is option d
Csc θ = 5/3