Answer:
Explanation:
There are a couple of ways you could do this.
The easiest is to use E*R1/(R1 + R2)
- E = 10 volts
- R1 = 590 ohms
- R2 = 840 ohms
So the result would be
E_590 = 10 * 590/(590 + 840)
E_590 = 10 * 590/ (1430)
E_590 = 4.13 volts rounded.
You could do this a slightly longer way.
R = 1430 (total ohms in series.
E = 10 volts
I = ???
I = E/R
I = 10 / 1430
I = 0.00699
Now use this current to figure out the voltage drop.
E = I * R
I = 0.00699 amps
R = 590 ohms
E = 0.00699 * 590
E = 4.13 volts
Pick the way of doing it you like best.
