If John has an apple, an orange, a pear, a banana, and a kiwi at home and he wants to bring two fruits for lunch, how many different pairs of fruit can he bring to school?

Respuesta :

Answer:

10

Step-by-step explanation:

5 choose 2 is 5x4/2, which is 20/2, which is 10.

The number of different pairs of fruit that John could bring to school is 10 given that he has an apple, an orange, a pear, a banana, and a kiwi at home. This can be obtained by using combination formula.

What is the formula for combination?

Combination is grouping of items,

⇒ ⁿCₓ = [tex]\frac{n!}{(n-r)!r!}[/tex] ,

where n is the number of items and r is number of selected items

Calculate the number of different pairs:

Given that there are 5 fruits and number of fruits that can be selected is 2.

Thus, n = 5 and r = 2

ⁿCₓ = ⁵C₂ = 5!/[(5-2)!2!] =5!/[3!2!] =120/12  =10

There are 10 different possible pairs of fruits.

Hence the number of different pairs of fruit that John could bring to school is 10 given that he has an apple, an orange, a pear, a banana, and a kiwi at home.

Learn more about permutation and combination here:

brainly.com/question/1458545

#SPJ2

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE