Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - given point
[tex]\bullet\ (2,\ 7),\ m=-4\\\\y-7=-4(x-2)\\\\\bullet(-6,\ -2),\ m=3\\\\y-(-2)=3(x-(-6))\to y+2=3(x+6)\\\\\bullet(12,\ 5),\ m=-3\\\\y-5=-3(x-12)\\\\\bullet(7,\ -6),\ m=\dfrac{1}{2}\\\\y-(-6)=\dfrac{1}{2}(x-7)\to y+6=\dfrac{1}{2}(x-7)\\\\\bullet(4,\ -5),\ m=6\\\\y-(-5)=6(x-4)\to y=y+5=6(x-4)\\\\\bullet(-8,\ 2),\ m=-\dfrac{3}{4}\\\\y-2=-\dfrac{3}{4}(x-(-8))\to y-2=-\dfrac{3}{4}(x+8)[/tex]
