Answer: 5=log_{2}(32)5=log
2
(32)
Step-by-step explanation:
1. By definition, you have if y=b^{x}y=b
x
, then x=log_{b}(y)x=log
b
(y)
2. Keeping this on mind, you must follow the proccedure shown below:
- You have that:
2^{5}=322
5
=32
Where:
\begin{lgathered}x=5\\y=32\\b=2\end{lgathered}
x=5
y=32
b=2
- Substitute values into x=log_{b}(y)x=log
b
(y) . Then, you obtain:
5=log_{2}(32)5=log
2
(32)
