Answer:
quotient is [tex]10x^2+3x-4[/tex]
Step-by-step explanation:
[tex]\frac{-40x^3-12x^2+16x}{-4x}[/tex]
To find the quotient we divide each term by -4x
[tex]\frac{-40x^3}{-4x} =10x^2[/tex]
Negative and negative becomes positive.
[tex]\frac{-12x^2}{-4x} =3x[/tex]
[tex]\frac{-16x}{-4x} =-4[/tex]
[tex]\frac{-40x^3-12x^2+16x}{-4x}=10x^2+3x-4[/tex]
