Answer:
A. (-1,-3) and (4,12)
Step-by-step explanation:
Make both equations equal to each other and solve for the variable x:
[tex]y=y\\3x=x^2-4\\x^2-3x-4=0\\[/tex]
Factor the expression. Find two numbers that when you add them you get -3 and the product of both numbers be -4. These numbers are 1 and -4. Then:
[tex](x+1)(x-4)=0\\\\x+1=0\\x=-1\\\\x-4=0\\x=4[/tex]
Substitute these values into one the original equations and solve for y:
[tex]y=3(-1)\\y=-3\\\\y=3(4)\\y=12[/tex]
Therefore, you get that the solution is:
(-1,-3) and (4,12)
