Answer:
Explanation:
As per Boltzman equation, kinetic energy (KE) is in direct relation to the temperature, measured in absolute scale Kelvin.
Then, the temperature at which the molecules of an ideal gas have 3 times the kinetic energy they have at any given temperature will be 3 times such temperature.
So, you must just convert the given temperature, 32°F, to kelvin scale.
You can do that in two stages.
T (K) = T(°C) + 273.15 K= 273.15 K
Then, 3 times gives you: 3 × 273.15 K = 819.45 K
Since, 32°F has two significant figures, you must report your answer with the same number of significan figures. That is 820 K.