Respuesta :
Answer:
C. The second equation in system B is [tex]-7x=14[/tex] .The solution to system B will be the same as the solution to system A.
Step-by-step explanation:
Given
System A:
[tex]5x-y=-11[/tex]
[tex]3x-2y=-8[/tex]
System B:
[tex]5x-y=-11[/tex]
When we multiply I equation of system A by -2 then we get new equation
[tex]-10x+2y=22[/tex] ( III equation )
Adding equation II of system A and eqaution III then we get
[tex]-7x=14[/tex]
Hence, II equation of system B
[tex]-7x=14[/tex]
By division property of equality
[tex]x=\frac{14}{-7}[/tex]
x=-2
Substitute the value of x=-2 in equation I of system B then we get
[tex]5(-2)-y=-11[/tex]
-10-y=-11
By simplification
[tex]-y=-11+10[/tex]=-1
y=1
By simplification
Therefore, the solution of system B is (-2,1).
Hence, option C is correct .
C. The second equation in system B is -7x=14 . The solution to system B will be the same as the solution to system A.