Monochromatic light with a wavelength of 6.4 E -7 meter passes through two narrow slits, producing an interference pattern on a screen 4.0 meters away. The first order bright band lines are 2.0 E -2 meters away from the central bright maxima.
What is the distance between the slits?

Respuesta :

1.3 E -4 m should be correct.

Answer:

The distance between the slits is [tex]1.3\times10^{-4}\ m[/tex].

Explanation:

Given that,

The wavelength of the monochromatic light [tex]\lambda= 6.4\times10^{-7}\ m[/tex]

Distance = 4.0 m

Width [tex]\beta = 2.0\times10^{-2}[/tex]

Using formula of the distance between the slits

[tex]d = \dfrac{n\lambda D}{x}[/tex]

Where, x = distance from central fringe

D = Distance between the slit and screen

d = distance between the slits

n = number of order

[tex]\lambda[/tex]=wavelength

Put the value into the formula

[tex]d=\dfrac{1\times6.4\times10^{-7}\times4.0}{2.0\times10^{-2}}[/tex]

[tex]d =1.3\times10^{-4}\ m[/tex]

Hence, The distance between the slits is [tex]1.3\times10^{-4}\ m[/tex].

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE