Answer:
[tex]0.0129 m^3[/tex]
Explanation:
The volume of the gas can be used by using the ideal gas equation:
[tex]pV=nRT[/tex]
where
p is the gas pressure
V is the gas volume
n is the number of moles of the gas
R is the gas constant
T is the absolute temperature of the gas
For the gas in this problem, we have
p = 1.10 atm is the pressure
V = ? is the volume
n = 0.600 mol is the number of moles
R = 0.082 L/atm K mol is the gas constant
T = 15.0 C + 273 = 288 K is the absolute temperature
Solving the equation for V, we find
[tex]V=\frac{nRT}{p}=\frac{(0.600 mol)(0.082 L/atm mol K)(288 K)}{1.10 atm}=12.9 L[/tex]
and converted into meters cubed, it is
[tex]V=12.9 L = 0.0129 m^3[/tex]
