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A ray of light is moving from a material having a high index of refraction into a material with a lower index of refraction.(a) Is the ray bent toward the normal or away from it?toward the normalaway from the normal (b) If the wavelength is 600 nm in the material with the high index of refraction, is it greater, smaller, or the same in the material with the lower index of refraction?greatersmaller the same(c) How does the frequency change as the light moves between the two materials?Does it increase, decrease, or remain the same?increasedecreaseremain the same

Respuesta :

(a) Away from the normal

The direction of bending of the ray of light can be found by using Snell's law:

[tex]n_1 sin \theta_1 = n_2 sin \theta_2[/tex]

where

n1, n2 are the index of refraction of the first and second medium, respectively

[tex]\theta_1, \theta_2[/tex] are the angle of the incident and refracted ray with respect to the normal to the surface, respectively

In this problem, the ray of light moves from a material with high index of refraction to a material with lower index, so:

[tex]n_1 > n_2[/tex]

Re-arranging Snell's law we find

[tex]sin \theta_2 = \frac{n_1}{n_2} sin \theta[/tex]

since

[tex]\frac{n_1}{n_2}>1[/tex]

we also have

[tex]sin \theta_2 > sin \theta_1\\\theta_2 > \theta_1[/tex]

so the ray of light bends away from the normal.

(b) The wavelength is greater in the second material (the one with lower index of refraction)

The wavelength of the light in a medium is given by

[tex]\lambda=\frac{\lambda_0}{n}[/tex]

where

[tex]\lambda_0[/tex] is the wavelength of the light in a vacuum

n is the refractive index

We can rewrite the equation as

[tex]\lambda_0 = \lambda_1 n_1 = \lambda_2 n_2[/tex]

And isolating [tex]\lambda_2[/tex] from the second equation

[tex]\lambda_2 = \frac{n_1}{n_2} \lambda_1[/tex]

where

[tex]\lambda_1 = 600 nm\\\frac{n_1}{n_2}>1[/tex]

So, we have that the wavelength in the second medium (the one with lower index of refraction) is longer than the wavelength in the first medium.

(c) The frequency is the same

While wavelength and speed of a light wave depend on the medium in which the wave is travelling through, the frequency does not depend on that, so it is exactly the same in the two mediums.

If ray of light moves from a material of high index of refraction into a material with a lower index of refraction;

  • The ray bends away from the normal
  • the wavelength decreases
  • the frequency remains constant.

What is refraction?

Refraction is the bending of light rays as they cross the boundary between two media of different densities.

The denser the medium the more the ray of light bends towards the normal and the more the speed of the wave decreases and vice versa.

Denser media has higher refractive index.

If a ray of light is moving from a material having a high index of refraction into a material with a lower index of refraction, the ray of light bends away from the normal.

Also, since wavelength is inversely proportional to speed, the wavelength is smaller in the material of lower refractive index.

The frequency of the wave is unaffected and remains contact.

Therefore, the wavelength, and speed of a light rays varies through media of different densities but the frequency remains constant.

Learn more about refraction at: https://brainly.com/question/1133363

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