Answer:
The gravitational acceleration on the planet is slightly less than g.
Explanation:
The period of a pendulum is given by:
[tex]T=2\pi \sqrt{\frac{L}{g}}[/tex]
where
L is the length of the pendulum
g is the acceleration due to gravity
The formula can also be rewritten as
[tex]g=(\frac{2\pi}{T})^2 L[/tex] (1)
In this problem, we have a pendulum which has a period of T=1.00 s on Earth. The length of the same pendulum must be shortened on the distant planet to have the same period of T'=1.00 s: this means that the length of the pendulum on the distant planet, L', is shorter than the length of the pendulum on Earth, L
[tex]L'<L[/tex]
By looking at formula (1), we see that g (the gravitational acceleration) is directly proportional to L. therefore, if L is shortened on the distant planet, it means that also the value of g is lower than on Earth:
so, the correct answer is
The gravitational acceleration on the planet is slightly less than g.
