Plz help me with this

Answer: [tex]\bold{\dfrac{1}{y^3}}[/tex]
Step-by-step explanation:
[tex]\dfrac{y^{-5}}{y^{-2}}\quad =\dfrac{y^{-5+5}}{y^{-2+5}}\quad =\dfrac{y^0}{y^3}\quad =\large\boxed{\dfrac{1}{y^3}}[/tex]
Answer:
[tex]\frac{1}{y^{3} }[/tex]
Step-by-step explanation:
Using the rule of exponents
• [tex]\frac{a^{m} }{a^{n} }[/tex] ⇔ [tex]\frac{1}{a^{(n-m)} }[/tex] → n > m
Hence
[tex]\frac{y^{-5} }{y^{-2} }[/tex] = [tex]\frac{1}{y^{(-2-(-5))} }[/tex] = [tex]\frac{1}{y^{3} }[/tex]