a circle centered at the origin contains the point (0,-9). does (8, square root 17) also lie on the circle? explain.

The radius of the circle is 9. If we imagine the distance to (8, sqrt 17) as a right triangle, where one leg is 8 and the other is square root 17, we can use the Pythagorean formula to solve this

8^2 (64) + sqrt 17^2 (17)= c^2

81=c^c

9=c

we can see that since the radius to the origin is 9, this point indeed lies on the circle.

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shivishivangi1679 shivishivangi1679 · Answer 2 · 2022-07-15T09:45:57+02:00

The radius to the origin is 9, this point indeed lies on the circle.

What is a circle?

A circle is a shape consisting of all points in a plane that are given the same distance from a given point called the center.

The distance to (8, √17) as a right triangle, where one leg is 8 and the other is √17, we can use the Pythagorean formula;

[tex]8^2 + \sqrt{17}^2 = c^2\\64 + 17 = c^2\\81=c^29=c[/tex]

Since the radius to the origin is 9, this point indeed lies on the circle.

Learn more about circle;

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