What is the equation to the given line in the point-slope form?


A. y = -x + 1
B. y + x = 1
C. y + x + 1 = 0
D. 4y = 3x + 1
E. y - 4 = 1(x-3)

What is the equation to the given line in the pointslope form A y x 1 B y x 1 C y x 1 0 D 4y 3x 1 E y 4 1x3 class=

Respuesta :

Answer:

E. y-4 = 1(x-3)

Step-by-step explanation:

The general form of the equation of a line is:

[tex](y-y_{0}) = m(x-x_{0})[/tex]

Where [tex]m = \frac{y_{1}-y_{0} }{x_{1}-x_{0}}[/tex]

To find the equation of the line we need two points. From the graph we get that those two points are: [tex]p_{1}= (0,1)  , p_{0}= (3,4)[/tex]

Then, we calculate m:

[tex]m = \frac{1-4 }{0-3}=1[/tex]

Then, the equation of the line is:

[tex](y-4) = 1(x-3)[/tex]

ANSWER

E. y - 4 = 1(x-3)

EXPLANATION

The equation of a line in point-slope form is found using the formula:

[tex]y-y_1=m(x-x_1)[/tex]

where m is the slope of the given line.

Since the line passes through (0,1) and (3,4), we can find the slope of the line using these two points.

The formula for calculating the slope is

[tex]m = \frac{y_2-y_1}{x_2-x_1} [/tex]

Plug in the points.

[tex]m = \frac{4 - 1}{3 - 0} = \frac{3}{3} = 1[/tex]

We put

[tex]x_1=3 \: and \: y_1=4[/tex]

as well as the slope in to the point-slope formula

to obtain:

[tex]y - 4 = 1(x - 3)[/tex]

Choice E is correct.
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