Respuesta :

If you mean find the a1, a2, a3, a4, a5, a6.

And so we can do that:

an=3an-1

and we know a1=-2

a2=3x(a2-1)

a2=-6

a3=2x(a3-1)

a3=-12

a4=3x(a4-1)

a4=-36

a5=3xa4

a5=-108

a6=3xa5

a6=-324

Answer:

the sequence will be ( -2, -6, -18, -54, -162, -486)

Step-by-step explanation:

We have find the first six term of the sequence whic is represented by

[tex]a_{(n)}=3.a_{(n-1)}[/tex]

amd [tex]a_{1}=(-2)[/tex]

First term [tex]a_{1}=(-2)[/tex]

[tex]a_{2}=3(a_{1} )=3(-2) =-6[/tex]

[tex]a_{3}=3(a_{2} )=3(-6) =-18[/tex]

[tex]a_{4}=3(a_{3} )=3(-18) =-54[/tex]

[tex]a_{5}=3(a_{4} )=3(-54) =-162[/tex]

[tex]a_{6}=3(a_{5} )=3(-162) =-486[/tex]

Therefore, the sequence will be ( -2, -6, -18, -54, -162, -486)

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