If you mean find the a1, a2, a3, a4, a5, a6.
And so we can do that:
an=3an-1
and we know a1=-2
a2=3x(a2-1)
a2=-6
a3=2x(a3-1)
a3=-12
a4=3x(a4-1)
a4=-36
a5=3xa4
a5=-108
a6=3xa5
a6=-324
Answer:
the sequence will be ( -2, -6, -18, -54, -162, -486)
Step-by-step explanation:
We have find the first six term of the sequence whic is represented by
[tex]a_{(n)}=3.a_{(n-1)}[/tex]
amd [tex]a_{1}=(-2)[/tex]
First term [tex]a_{1}=(-2)[/tex]
[tex]a_{2}=3(a_{1} )=3(-2) =-6[/tex]
[tex]a_{3}=3(a_{2} )=3(-6) =-18[/tex]
[tex]a_{4}=3(a_{3} )=3(-18) =-54[/tex]
[tex]a_{5}=3(a_{4} )=3(-54) =-162[/tex]
[tex]a_{6}=3(a_{5} )=3(-162) =-486[/tex]
Therefore, the sequence will be ( -2, -6, -18, -54, -162, -486)