if we call the area A, then [tex]A=7(x+2)=7x+14[/tex] if we call the perimeter P, then [tex]P=7*2+2(x+2)=2x+18[/tex] [tex]A>P[/tex] [tex]7x+14>2x+18[/tex] subtracting 14 gives [tex]7x>2x+4[/tex] subtracting 2x gives [tex]5x>4[/tex] dividing by 5 gives [tex]x>\frac{4}{5}[/tex] or [tex]x>0.8[/tex]
