Find two consecutive numbers if the square root of the smaller number is 3 less than the bigger number.

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calculista calculista · Answer 1 · 2019-03-31T06:27:08+02:00

Answer:

The numbers are 4 and 5

Step-by-step explanation:

Let

x------> the smaller number

x+1----> the bigger number

we know that

[tex]\sqrt{x}=(x+1)-3[/tex] ----> equation that represent the situation

solve for x

[tex]\sqrt{x}=(x-2)[/tex]

squared both sides

[tex]x=(x-2)^{2}\\x=x^{2}-4x+4\\x^{2}-5x+4=0[/tex]

using a graphing calculator to solve the quadratic equation

see the attached figure

the solution is

[tex]x=4[/tex]

[tex]x+1=5[/tex]

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raphealnwobi raphealnwobi · Answer 2 · 2022-03-08T11:31:28+01:00

The consecutive numbers are 4 and 5 in which the square root of the smaller number is 3 less than the bigger number

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the smaller number and y the larger number, hence:

y = x + 1 (1)

Also:

[tex]\sqrt{x} =y-3[/tex] (2)

From equation 1 and 2:

x = 4, and y = 5

The consecutive numbers are 4 and 5

Find out more on Equation at: https://brainly.com/question/2972832