Respuesta :
1. Answer;
4 m/s²
Explanation;
When both forces point due east then;
the resultant force will be; 10 + 30 = 40 N due east
But; From second Newton's law of motion;
F = ma
Thus;
a = F/m ; F= 40 N and mass = 10 kg
= 40/ 10
= 4 m/s² to wards east
2. Answer;
1 m/s²
Explanation;
when 10 N force points due east and 30 N force points due west then;
the resultant force will be; 30 N - 10 N = 10 N due west
But; From second Newton's law of motion;
F = ma
Thus;
a = F/m
= 10 /10
= 1 m/s² , towards the west direction
Explanation:
Given that,
First force = 10 N
Second force = 30 N
Mass of box = 10 kg
(1). When both forces point due east
Then the net force will be
[tex]F_{net}=F_{1}+F_{2}[/tex]
[tex]F_{net}=10+30[/tex]
[tex]F=40 N[/tex]
We need to calculate the acceleration
Using newton's second law
[tex]F= ma[/tex]
put the value into the formula
[tex]40=10\times a[/tex]
[tex]a=\dfrac{40}{10}[/tex]
[tex]a=4\ m/s^2[/tex]
The box accelerate towards east.
(2). When 10 N force points due east and 30 N force points due west.
Then the net force will be
[tex]F_{net}=F_{2}-f_{1}[/tex]
[tex]F_{net}=30-10=20\ N[/tex]
We need to calculate the acceleration
Using newton's second law
[tex]F= ma[/tex]
[tex]20=10\times a[/tex]
[tex]a=\dfrac{20}{10}[/tex]
[tex]a=2\ m/s^2[/tex]
The box accelerate towards west.
Hence, This is the required solution.
