Respuesta :
solve the system with elimination
multiply the first equation by two to cancel
2(2x-y=5) new equation 4x-2y=10
now the -2y and 2y cancel each other out
now you have 4x=10 + 3x=4 = 7x=14
divide by 7 to get x=2 now we have to find y by plugging x into one of the equations(let's use the first one)
2(2)-y=5 --> 4-y=5 --> -y =1 --> y =-1
(x,y) (2,-1)
multiply the first equation by two to cancel
2(2x-y=5) new equation 4x-2y=10
now the -2y and 2y cancel each other out
now you have 4x=10 + 3x=4 = 7x=14
divide by 7 to get x=2 now we have to find y by plugging x into one of the equations(let's use the first one)
2(2)-y=5 --> 4-y=5 --> -y =1 --> y =-1
(x,y) (2,-1)
Solving the system of equation, we get Option (C) (2,-1).
How to solve the given set of equations ?
The equations given are 2x - y = 5 and 3x + 2y = 4.
To find the point which solves the two equation, we have to satisfy the given x and y coordinates of the point on the given two equations.
Checking all the other Options, it does not satisfies except Option (C).
Checking the point (2,-1) on the first equation 2x - y = 5 , we get 5 in the left hand side of the equation.
Again checking the point (2,-1) on the second equation 3x + 2y = 4 , we get 4 in the left hand side of the equation.
Therefore the coordinates (2,-1) (Option C) satisfies both the equation which is the required solution.
To learn more about solving system of equation, refer -
https://brainly.com/question/7808225
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