For this case we have that the volume of a cylinder is given by:
[tex]V_ {1} = \pi * r ^ 2 * h[/tex]
And the volume of a cone is given by:
[tex]V_ {2} = \frac {1} {3} * \pi * r ^ 2 * h[/tex]
Where:
A: It's the radio
h: It's the height
In this case:
[tex]V_ {1} = 2512 \ in ^ 3\\V_ {2} = 1256 \ in ^ 3[/tex]
And the height is the same for both.
For the area of the bases to be equal, the volume of the cylinder must be 3 times the volume of the cone.
It is observed that:
[tex]1256 \ in ^ 3 * 3 =\\3768 \ in ^ 3[/tex]
Then, it is not fulfilled.
Answer:
Option D
