An object of mass m slides down an incline with angle 0.

Any frictional forces (due to static friction or kinetic friction, if applicable) along the incline
The corresponding force component along the incline (downhill force due to gravity)

Force due to gravity = -mgcosΔ

Normal force = fN

Frictional force = -f

force applied forward = mgsinΔ

Horizontal force = mgsinΔ - f

vertical force = fN - mgcosΔ

aristocles aristocles · Answer 2 · 2019-07-23T02:31:57+02:00

Answer:

B). [tex]F_N - mgcos\theta = 0[/tex]

Explanation:

As we know that the force on the mass "m" which slides along the inclined plane is along the inclined surface

So it must have accelerated along that surface only

So we can write the equation for force along the inclined plane as

[tex]F_{net} = ma[/tex]

now if we wish to find net force perpendicular to the plane then we can say that it must be zero

Because perpendicular to the plane the net force on the given mass must be zero as it is not accelerating along that direction

So here we can say

[tex]F_{net} = 0[/tex]

so we have

[tex]F_N - mgcos\theta = 0[/tex]