Respuesta :
Answer:
y = -4/36 * (x-6)^2 + 4
Step-by-step explanation:
The quadratic equation expressed in vertex from is
y = a(x-h)^2 + k
The vertex is
Vertex = (h,k) = (6,4)
This means
y = a(x-6)^2 + 4
To find a, we know that at 12 feet from the water jet, the height is equal to zero.
0 = a(12-6)^2 + 4
a = -4/36
Therefore, the equation is
y = -4/36 * (x-6)^2 + 4
Please see attached graph for reference.

The vertex form that models the path of the stream is y = (-1/9)(x - 6)² + 4
Equation of a parabola?
The equation of a parabola in vertex form is given by:
y = a(x - h)² + k
Where (h, k) is the vertex
Given the parabola has vertex of (6,4), hence:
y = a(x - 6)² + 4
At point (12, 0):
0 = a(12 - 6)² + 4
a = -1/9.
y = (-1/9)(x - 6)² + 4
The vertex form that models the path of the stream is y = (-1/9)(x - 6)² + 4
Find out more on parabola at: https://brainly.com/question/4148030