Answer:
[tex]2.43\cdot 10^5 J[/tex]
Explanation:
Since the force applied is parallel to the displacement of the car, the work done on the car is simply given by:
[tex]W=Fd[/tex]
where
F = 1210 N is the force applied on the car
d = 201 m is the displacement of the car
Substituting numbers into the equation, we find:
[tex]W=(1210 N)(201 m)=2.43\cdot 10^5 J[/tex]
