A student in Greece discovers a pottery bowl that contains 48% of its original amount of C-14. Find the age of the pottery of bowl to the nearest year.

A student in Greece discovers a pottery bowl that contains 48 of its original amount of C14 Find the age of the pottery of bowl to the nearest year class=

Respuesta :

The correct answer is 4780

Answer:

7340 years

Step-by-step explanation:

A student in Greece discovers a pottery bowl that contains 48% of the original C-14.

Decay of C - 14 is represented by the expression given

N = [tex]N_{0}e^{-kt}[/tex]

where, [tex]N_{0}[/tex] = initial quantity of C-14 = 100% = 1

N = quantity of C-14 after t years = 48% = 0.48

k = 0.0001

and t = time in years.

We have to find the age of the bowl.

0.48 =  [tex]1(e)^{(-0.001)(t)}[/tex]

By taking natural logarithm

ln ( 0.48 ) = ln [tex]e^{(-0.0001)(t)}[/tex]

-0.73397 = -0.0001t  [ since ln e = 1 ]

t = [tex]\frac{0.73397}{0.0001}[/tex]

t = 7340 years

Age of the pottery of bowl is 7340 years.

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE