A bag contains 4 blue coins and 8 red coins. A coin is removed at random and replaced by three of the other color.

Part 2 out of 3
If the first coin removed is blue, what is the probability of drawing a red coin after three red coins are put in the bag to replace the blue one?

the answer is 11/14 because you remove one blue coin and add three red coins and in total in the bag there are 14 coins. you then create a fraction by putting the 11 red coins over the 14 total coins to get the probability of what you will get

The answer is 11/14

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A bag contains 4 blue coins and 8 red coins. A coin is removed at random and replaced by three of the other color. Part 2 out of 3 If the first coin removed is blue, what is the probability of drawing a red coin after three red coins are put in the bag to replace the blue one?

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A bag contains 4 blue coins and 8 red coins. A coin is removed at random and replaced by three of the other color.

Part 2 out of 3
If the first coin removed is blue, what is the probability of drawing a red coin after three red coins are put in the bag to replace the blue one?