The opposite angles of a quadrilateral inscribed in a circle adds up to 180°.
This means that angles A and C add up to 180°, so do angles B and D.
Therefore, (x - 10) + (x - 2) = 180°
2x - 12 = 180°
2x = 192°
x = 96°
Hence,
Angle A = 96° - 10° = 86°
Angle B = 180° - (96° + 2°) = 82°
Angle C = 96° - 2° = 94°
Angle D = 96° + 2° = 98°
