Answer:
1) [OH⁻] = 0.065 M
2) [H₃O⁺] = 1.54 x 10⁻¹³ M.
3) pH = 12.81.
Explanation:
HCl is completely dissociated yo its ions in solution:
KOH + H₂O → H₃O⁺ + K⁺ + OH⁻,
1) [OH⁻] = 0.065 M.
2) [H₃O⁺]:
∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.
∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(0.065 M) = 1.54 x 10⁻¹³ M.
3) pH:
For strong acids like HCl:
pH = - log[H₃O⁺] = - log[1.54 x 10⁻¹³ M] = 12.81.
